2/π arcsin (4,5-2x+15x в квадрате - 6 х в кубе) = 1/√3 ctg (-46π/3)

решение?

2/π arcsin (4,5-2x+15x^2 - 6 х^3) = 1/√3 ctg (-46π/3)

4,5-2x+15x^2 - 6 х^3 = t

2/π arcsint = 1/√3 ctg (-46π/3)

2/π arcsint = 1/√3 * (-1/√3)

2/π arcsint = - 1/3

arcsint = - П/6

t = sin (-П/6)

t = - 1/2

4,5-2x+15x^2 - 6 х^3 = - 0,5

6x^3 - 15x^2 + 2x - 5 = 0

2x (3x^2 + 1) - 5 (3x^2 + 1) = 0

(3x^2 + 1) (2x - 5) = 0

3x^2 + 1 = 0 2x - 5 = 0

3x^2 = - 1 х = 2,5

нет решений