Sin (3x+3) = cos (x-1) решите

Sin (3x + 3) - cos (x - 1) = 0

Sin (3x + 3) - Sin (π/2 - x + 1) = 0

2Sin (3x + 3 - π/2 + x - 1) / 2 Cos (3x + 3 + π/2 - x + 1) / 2 = 0

а) Sin (3x + 3 - π/2 + x - 1) / 2 = 0 или б) Cos (3x + 3 + π/2 - x + 1) / 2

Sin (4x + 2 - π/2) / 2=0 Cos (2x + π/2 + 4) / 2 = 0

- Sin (π/2 - 4x - 2) / 2 = 0 x + π/4 + 2 = π/2 + πk, k∈Z

Sin (π/4 - 2x - 1) = 0 x = π/2 + πк - π/4 - 2, к ∈Z

π/4 - 2x - 1 = πn< n∈Z x = π/4 + πк - 2, к∈Z

-2x = πn - π/4 + 1, n ∈Z

x = - πn/2 + π/8 - 1/2, n ∈Z