sin (x/2 - π/6) + 1=0

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Алгебра

Ксеша

21 декабря, 08:49

sin (x/2 - π/6) + 1=0

+3

Ответы (2)

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Коста · Answer 1

sin (x/2 - π/6) + 1=0

sin (x/2 - π/6) = - 1

x/2 - π/6 = - π/2 + 2πn

x/2 = π/6-π/2 + 2πn

x/2 = - 2π/6 + 2πn

x = - 2π/3 + 4πn

Володюня · Answer 2

sin (x/2 - π/6) + 1=0

1 = sin (π/2)

sin (x/2 - π/6) + sin (π/2) = 0

sin (x/2 - π/6) = - sin (π/2)

sin (x/2 - π/6) = sin (-π/2)

x/2 - π/6 = (3x - π) / 6

(3x - π) / 6 = - π/2

3x - π + 3π = 0

3x + 2π = 0

3x = - 2π

x = - 2π/3

Ответ: - 2π/3