1 вариант

1) cosx = 1/2

3) tgx = 1

4) cos (x+П/3) = 0

5) 2cosx = 1

6) 3tgx = 0

7) sin4x = 1

Question

Математика

Вячеслав

23 июля, 15:07

1 вариант

1) cosx = 1/2

3) tgx = 1

4) cos (x+П/3) = 0

5) 2cosx = 1

6) 3tgx = 0

7) sin4x = 1

+2

Ответы (1)

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Федосья · Answer 1

1. + - π/3+πk, k∈z,

2. π/4+πk, k∈z,

3. x+π/3=π/2+πk, k∈z,

x=π/2-π/3+πk, k∈z,

x=π/6+πk, k∈z,

4. cosx=1/2,

x=+-π/3+πk, k∈z,

5. tgx=0,

x=πk, k∈z,

6.4x=π/2+2πk, k∈z,

x=π/8 + (1/2π) k, k∈z

1 вариант1) cosx = 1/23) tgx = 14) cos (x+П/3) = 05) 2cosx = 16) 3tgx = 07) sin4x = 1

1 вариант

1) cosx = 1/2

3) tgx = 1

4) cos (x+П/3) = 0

5) 2cosx = 1

6) 3tgx = 0

7) sin4x = 1