Решите неравенство

((x^2-12x+10) / (x-1)) + ((x^2-15x+5) / (x-5)) = <2x-11

(x^2-12x+10) / (x-1) + (x^2-15x+5) / (x-5) ≤ 2x-11

[ (x^2-12x+10) (x-5) + (x^2-15x+5) (x-1) - (2x-11) (x-1) (x-5) ] / [ (x-1) (x-5) ] ≤ 0

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(x^2-12x+10) (x-5) - (2x-11) (x-1) (x-5) =

= (x^2-12x+10-2x^2+13x-11) (x-5) =

= (-x^2+x-1) (x-5) =

= - x^3+x^2-x+5x^2-5x+5 =

= - x^3+6x^2-6x+5

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(x^2-15x+5) (x-1) =

= x^3-15x^2+5x-x^2+15x-5 =

= x^3-16x^2+20x-5

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-x^3+6x^2-6x+5+x^3-16x^2+20x-5 =

= - 10x^2+14x

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-2x (5x-7) / [ (x-1) (x-5) ] ≤ 0

2x (5x-7) / [ (x-1) (x-5) ] ≥ 0

x≠1; x≠5

_+_[0]_-_ (1) _+_[1.4]_-_ (5) _+_

Ответ:

(-∞; 0] ∨ (1; 1.4] ∨ (5; +∞)