1) f (x) = 4x²-6x, x0=2

2) f (x) = x²-2x, x0=3

3) f (x) = 3x²-8x+7, x0=1

4) f (x) = 3x-4x²+20, x0=-2

Question

Математика

Таися

23 сентября, 23:29

1) f (x) = 4x²-6x, x0=2

2) f (x) = x²-2x, x0=3

3) f (x) = 3x²-8x+7, x0=1

4) f (x) = 3x-4x²+20, x0=-2

+4

Ответы (1)

Знаете ответ на вопрос?

Евгеня · Answer 1

1. f (x) = 4x^2-6x

f' (x) = 8x - 6

f (2) = 8*2 - 6 = 10

2. f (x) = x²-2x, x0=3

f' (x) = 2x - 2

f (3) = 2*3 - 2 = 4

3. f (x) = 3x²-8x+7, x0=1

f' (x) = 6x - 8

f (1) = 6-8 = - 2

4. f (x) = 3x-4x²+20, x0=-2

f' (x) = 3-8x

f (2) = 3 - (-8) * (-2) = 3 + 16 = 19

1) f (x) = 4x²-6x, x0=22) f (x) = x²-2x, x0=33) f (x) = 3x²-8x+7, x0=14) f (x) = 3x-4x²+20, x0=-2

1) f (x) = 4x²-6x, x0=2

2) f (x) = x²-2x, x0=3

3) f (x) = 3x²-8x+7, x0=1

4) f (x) = 3x-4x²+20, x0=-2