Помогите решить! arctg (-√3) · arcctg (-1) - arcsin (-√3/2) · arccos (-√3/2) + arcctg (-1/√3) ·arcsin (-√2/2)

arctg (-√3) · arcctg (-1) - arcsin (-√3/2) · arccos (-√3/2) +

+ arcctg (-1/√3) ·arcsin (-√2/2) = - arctg (√3)*( π - arcctg 1) + arcsin (√3/2)*( π -

arccos (√3/2)) + ( π - arcctg(1/√3))*( - arcsin (√2/2)) = - ( π/3)*( π - π/4 ) +

(π/3)*( π - π/6 ) - ( π - π/3)*( π/4) = - ( π/3)*(3π/4) + (π/3)*(5π/6) - (2π/3)*(π/4)=

- (π²/4) + (5π²/18) - (π²/6) = - (5π²/36) .

В - дь : - (5π²/36) .