1) - 5 (4,2y+1) + 4 (1,4y-2) = - 20,2

2) - 5/7 - (m-1) = 11/14

3) 1 5/6 - (y+2/3) = 1 1/2

Question

Математика

Драгана

5 августа, 18:43

1) - 5 (4,2y+1) + 4 (1,4y-2) = - 20,2

2) - 5/7 - (m-1) = 11/14

3) 1 5/6 - (y+2/3) = 1 1/2

+3

Ответы (1)

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Солвита · Answer 1

1) - 21y-5+5.6y-8=-20.2

-15.4y-13=-20.2

-15.4y=-20.2+13

-15.4y=-7.2

y=36/77

2) - 5/7-m+1=11/14

-m+2/7=11/14

-m=11/14-2/7

-m=0.5

m=-0.5

3) 1 5/6-y-2/3=1 1/2

-y+1 1/6=1 1/2

-y=1 1/2 - 1 1/6

-y=-1/3

y=1/3

1) - 5 (4,2y+1) + 4 (1,4y-2) = - 20,22) - 5/7 - (m-1) = 11/143) 1 5/6 - (y+2/3) = 1 1/2

1) - 5 (4,2y+1) + 4 (1,4y-2) = - 20,2

2) - 5/7 - (m-1) = 11/14

3) 1 5/6 - (y+2/3) = 1 1/2