39x + (4x+3) ^2=2+4 (2x+1) ^2 решить уравнение

39x + (4x+3) ^2=2+4 (2x+1) ^2

39x+16x^2+24x+9=2+4 (4x^2+4x+1)

16x^2+63x+9=16x^2+16x+6

63x-16x=6-9

47x=-3

x=-3/47

39x + (4x + 3) ² = 2 + 4 (2x + 1) ²

39x + 16x² + 24x + 9 = 2 + 4 (4x² + 4x + 1)

63x + 9 = 16x + 6

47x = - 3

x = - 3/47

-117/47 + (-12/47 + 3) ² = 2 + 4 (-6/47 + 1) ²

-117/47 + (129/47) ² = 2 + 4 (41/47) ²

-117/47 + 16641/2209 = 2 + 6724/2209

(16641 - 5499) / 2209 = (4418 + 6724) / 2209

11142 = 11142

Если в условии второй знак не +, а -

39x + (4x - 3) ² = 2 + 4 (2x + 1) ²

39x + 16x² - 24x + 9 = 2 + 4 (4x² + 4x + 1)

15x + 9 = 16x + 6

x = 3

39*3 + (12 - 3) ² = 2 + 4 (6 + 1) ²

117 + 81 = 2 + 4*49

198 = 198