Вычислите:

1) 2/3 * (3/4+5/8) = ?

2) 2-5/6:8/9=?

3) 2/3: (3/4-5/12) = ?

4) 3-2/36/7=?

5) 3/5 (4/21+2/7) = ?

6) 3-1/10:2/15=?

7) 5/6: (3/4-1/12) = ?

8) 2-3/8*4/5=?

Question

Математика

Дионисия

22 марта, 18:01

Вычислите:

1) 2/3 * (3/4+5/8) = ?

2) 2-5/6:8/9=?

3) 2/3: (3/4-5/12) = ?

4) 3-2/36/7=?

5) 3/5 (4/21+2/7) = ?

6) 3-1/10:2/15=?

7) 5/6: (3/4-1/12) = ?

8) 2-3/8*4/5=?

+5

Ответы (1)

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Васюха · Answer 1

=2/3 * (6/8+5/8) = 2/3*11/8=11/12

=2-5/6*9/8=2-15/16=1 1/16

=2/3: (9/12-5/12) = 2/3:4/12=2/3*12/4=4/2=2

=3-4/7=2 3/7

=3/5 * (4/21+6/21) = 3/5*10/21=2/7

=3-1/10*15/2=3-3/4=2 1/4

=5/6: (9/12-1/12) = 5/6:8/9=5/6*9/8=15/16

=2-3/10=1 7/10

Вычислите:1) 2/3 * (3/4+5/8) = ?2) 2-5/6:8/9=?3) 2/3: (3/4-5/12) = ?4) 3-2/3*6/7=?5) 3/5 * (4/21+2/7) = ?6) 3-1/10:2/15=?7) 5/6: (3/4-1/12) = ?8) 2-3/8*4/5=?

Вычислите:

1) 2/3 * (3/4+5/8) = ?

2) 2-5/6:8/9=?

3) 2/3: (3/4-5/12) = ?

4) 3-2/36/7=?

5) 3/5 (4/21+2/7) = ?

6) 3-1/10:2/15=?

7) 5/6: (3/4-1/12) = ?

8) 2-3/8*4/5=?