1) 0,3m+2 (0,2m-0,3) = 0,8-0,7 (m-2)

2) 0,6 - (1,3+1) = 2,8x-13,52

3) 1/8 (8/9y+8) - 1/5 (5/6y+1 2/3) = 2

Question

Математика

Егорий

27 мая, 15:44

1) 0,3m+2 (0,2m-0,3) = 0,8-0,7 (m-2)

2) 0,6 - (1,3+1) = 2,8x-13,52

3) 1/8 (8/9y+8) - 1/5 (5/6y+1 2/3) = 2

+4

Ответы (1)

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Маркел · Answer 1

1) 0.3m+2 (0.2m-0.3) = 0.8-0.7 (m-2)

0.3m+0.4m-0.6=0.8-0.7m-1.4

0.7m-0.6=-0.6-0.7m

0.7m-0.7m=0.6-0.6

0=0

2) 0.6 - (1.3+1) = 2.8x-13.52

0.6-2.3=2.8x-13.52

2.8x-13.52+1.7

2.8x=15.22

x=15.22/2.8

x=5.43571

1) 0,3m+2 (0,2m-0,3) = 0,8-0,7 (m-2)2) 0,6 - (1,3+1) = 2,8x-13,523) 1/8 (8/9y+8) - 1/5 (5/6y+1 2/3) = 2

1) 0,3m+2 (0,2m-0,3) = 0,8-0,7 (m-2)

2) 0,6 - (1,3+1) = 2,8x-13,52

3) 1/8 (8/9y+8) - 1/5 (5/6y+1 2/3) = 2