А) log3 27

б) log5 1/25

в) log2 x=-3

г) log0,1 x=-2

д) logx 16=2

А) log_3 (27) = > 3 ˣ=27 = > x=3

log_3 (27) = 3

б) log_5 (1/25) = > 5 ˣ=1/25 = > 5ˣ=1/5² = > 5ˣ=5⁻² = > x=-2

log_5 (1/25) = - 2

в) log_2 (x) = - 3 = > x=2 ⁻³ = > x=0.125

log_2 (0.125) = - 3

г) log_0,1 (x) = - 2 = > x=0.1 ⁻² = > x=100

log_0.1 (100) = - 2

д) log_x (16) = 2 = > x ²=16 = > x=√16 = > x=4

log_4 (16) = 2