Сократите дробь

(18^ (n+1)) / ((3^ (2n+5)) * (2^ (n-2)))

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Математика

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27 мая, 11:37

Сократите дробь

(18^ (n+1)) / ((3^ (2n+5)) * (2^ (n-2)))

+3

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Викторыч · Answer 1

(18^ (n+1)) / ((3^ (2n+5)) * (2^ (n-2))) = (2^ (n+1)) (9^ (n+1)) / ((3^ (2n+5)) * (2^ (n-2))) = (2^ (n+1)) (3^ (2n+2)) / ((3^ (2n+5)) * (2^ (n-2))) = (2^ (n+1-n+2)) (3^ (2n+2-2n-5)) = 2^3*3^-3=8/27

Сократите дробь(18^ (n+1)) / ((3^ (2n+5)) * (2^ (n-2)))

Сократите дробь

(18^ (n+1)) / ((3^ (2n+5)) * (2^ (n-2)))