Помогите крик души. Решите подробно. Система уравнении.

{8^x+8^y=72

{x+y=3

Найдите |x1-x2|

Ответ будет: 1

{x+y=3

{8^x+8^y=72

{x=3-y

{8^ (3-y) + 8^y=72

8^ (3-y) + 8^y = 72

8^3/8^y + 8^y = 72

(8^3 + (8^y) * (8^y) - 72*8^y) / 8^y = 0

(8^y) ^2 - 72*8^y + 8^3 = 0

---

8^y=t

t^2 - 72t + 8^3 = 0

D = (9^2) * (8^2) - 4*8^3 = (8^2) * (81-32) = (8^2) * (7^2) = 56^2

[t1 = (72+56) / 2=64

[t2 = (72-56) / 2=8

[ {t1=64

[ {8^y1=8^2 y1=2

[

[ {t1=8

[ {8^y2=8 y2=1

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[ {y1=2

[ {x1=3-2=1

[

[ {y2=1

[ {x2=3-1=2

|x1-x2| = |1-2| = |-1| = 1