Решите уравнение:

а) (4-x) + 1 1/5=3 7/560

б) 4 3/5 + (y-2 5/6) = 5 2/3

в) 1 2/3 + (t-2 3/8) = 1/24+5 1/2

г) (7 1/12-k) - 1 1/3=6 13/18-2 1/4

А) (4-x) + 1 1/5=3 7/560

4 - х + 6/5 = 1687/560

- х = 1687/560 - 4 - 6/5

-х = 1687/560 - 2240/560 - 672/560

х = 245/112 = 2 ц 1/112

б) 4 3/5 + (y-2 5/6) = 5 2/3

23/5 + у - 17/6 = 17/3

у = 17/3 + 17/6 - 23/5

у = 51/6 - 23/5

у = 39/10 = 3,9

в) 1 2/3 + (t-2 3/8) = 1/24+5 1/2

5/2 + t - 19/8 = 1/24 + 11/2

t = 1/24 + 11/2 - 5/2 + 19/8

t = 1/24 + 6/2 + 19/8

t = 130/24 = 65/12 = 5 ц 5/12

г) (7 1/12-k) - 1 1/3=6 13/18-2 1/4

85/12 - к - 4/3 = 121/18 - 9/4

-к = 121/18 - 9/4 - 69/12

-к = 121/18 - 48/6

к = 23/18 = 1 ц 5/18