Протабулировать функцию в паскале

Условия: (сумма) S=1+3x^/1!+5x^4/2! + ...

(диапазон изменений [0,1; 1]

n=10

(функция) y = (1+2x^2) * e^x^2

Const e=0.001;

var x, xn, h, an, s, f, y:real; n, k, i:integer;

begin

n:=10;

h: = (1-0.1) / (n-1) ;

x:=0.1-h;

for i:=1 to n do

begin

x:=x+h; an:=1;

xn:=1; f:=1;

k:=0; s:=1;

while an>e do

begin

xn:=xn*x*x;

k:=k+1;

f:=f*k;

an: = (2*k+1) * xn/f;

s:=s+an;

end;

y: = (1+2*x*x) * exp (x*x) ;

writeln ('x = ', x:4:1,' s = ', s:6:4,' y = ', y:6:4) ;

end;

end.

Результат:

x = 0.1 s = 1.0303 y = 1.0303

x = 0.2 s = 1.1241 y = 1.1241

x = 0.3 s = 1.2911 y = 1.2911

x = 0.4 s = 1.5490 y = 1.5490

x = 0.5 s = 1.9260 y = 1.9260

x = 0.6 s = 2.4653 y = 2.4653

x = 0.7 s = 3.2320 y = 3.2320

x = 0.8 s = 4.3240 y = 4.3240

x = 0.9 s = 5.8894 y = 5.8895

x = 1.0 s = 8.1548 y = 8.1548