W (C) = 53.33%

w (H) = 15.56%

w (N) = 31.11%

D (Ne) = 2.25

Найти:CxHyNz

Question

Химия

Кадербанат

5 февраля, 14:27

W (C) = 53.33%

w (H) = 15.56%

w (N) = 31.11%

D (Ne) = 2.25

Найти:CxHyNz

+2

Ответы (1)

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Нифоя · Answer 1

CxHyNz = r

D (r) (Ne) = 2.25 = = > M (r) = 2.25 * 20 = 45 г/моль

n (C) = (53.33*45) / 1200 = 2

n (H) = (15.56*45) / 100 = 7

n (N) = (31.11*45) / 1400 = 1

C2H7N;

NH2C2H5 - этиламин.

W (C) = 53.33%w (H) = 15.56%w (N) = 31.11%D (Ne) = 2.25Найти:CxHyNz

W (C) = 53.33%

w (H) = 15.56%

w (N) = 31.11%

D (Ne) = 2.25

Найти:CxHyNz