ctg² (2t-π/3) = 3

tg² (3t+π/2) = 1/3

|sin (3t) | = 1/2

Question

Алгебра

Петруша

20 февраля, 10:18

ctg² (2t-π/3) = 3

tg² (3t+π/2) = 1/3

|sin (3t) | = 1/2

+5

Ответы (1)

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Дашура · Answer 1

ctg (2t-П/3) = + - sqrt (3)

2t-П/3=+-П/6+Пk

2t=П/2+Пk 2t=П/6+Пk

t=П/4+Пk/2 t=П/12+Пk/2

ctg (3t) = + - sqrt (3) / 3

3t=+-П/3+Пk

t=+-П/9+Пk/3

sin3t=1/2 sin3t>=0

sin3t=-1/2 sin3t<0

3t=+-П/6+2 Пk t=+-П/18+2 пk/3

3t=+-5 П/6+2 Пk t=+-5 П/18+2 пk/3

ctg² (2t-π/3) = 3tg² (3t+π/2) = 1/3|sin (3t) | = 1/2

ctg² (2t-π/3) = 3

tg² (3t+π/2) = 1/3

|sin (3t) | = 1/2