Решите уравнения: (x²-5x) + 5-x=0; 3x²-18x + (6-x) = 0; x²-9x - (x-9) = 0; 4x-x² - (2x-8) = 0.

1) (x²-5x) + 5-x=0

x (x-5) - (x-5) = 0

(x-5) (x-1) = 0

x-5=0 x-1=0

x=5 x=1

Ответ: 1; 5.

2) 3x²-18x + (6-x) = 0

3x (x-6) - (x-6) = 0

(x-6) (3x-1) = 0

x-6=0 3x-1=0

x=6 3x=1

x=1/3

Ответ: 1/3; 6.

3) x²-9x - (x-9) = 0

x (x-9) - (x-9) = 0

(x-9) (x-1) = 0

x-9=0 x-1=0

x=9 x=1

Ответ: 1; 9.

40 4x-x² - (2x-8) = 0

x (4-x) + 2 (4-x) = 0

(4-x) (x+2) = 0

4-x=0 x+2=0

x=4 x = - 2

Ответ: - 2; 4.