ax+ay+az=

-ax-bx-cx=

(m+1) - m (m+1) =

2 (a-b) + c (b-a) =

4 (m+n) + (m+n) =

2a (b-3) - 5c (3-b) =

Question

Алгебра

Иулия

15 марта, 09:47

ax+ay+az=

-ax-bx-cx=

(m+1) - m (m+1) =

2 (a-b) + c (b-a) =

4 (m+n) + (m+n) =

2a (b-3) - 5c (3-b) =

+2

Ответы (1)

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Лазарь · Answer 1

ax+ay+az = а (х+у+z)

-ax-bx-cx = - х (а+в+с)

(m+1) - m (m+1) = (1-m) (1+m) = 1 - m^2

2 (a-b) + c (b-a) = (2-с) (а-в)

4 (m+n) + (m+n) = (4+1) (m+n) = 5 (m+n)

2a (b-3) - 5c (3-b) = (2 а+5 с) (в-3)

Ура!)

ax+ay+az=-ax-bx-cx=(m+1) - m (m+1) =2 (a-b) + c (b-a) =4 (m+n) + (m+n) =2a (b-3) - 5c (3-b) =

ax+ay+az=

-ax-bx-cx=

(m+1) - m (m+1) =

2 (a-b) + c (b-a) =

4 (m+n) + (m+n) =

2a (b-3) - 5c (3-b) =