Cos (2x+pi/4) = 0

sin (x+3pi/4) = 0

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Сегодня, 21:12

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Ответы (2)

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Пашуха · Answer 1

Cos (2x+π/4) = 0;

cos (π/2) = 0;

2x+π/4=π/2;

2x=π/2-π/4;

2x=π/4;

x=π/8.

sin (x+3π/4) = 0;

sin (0) = 0;

x+3π/4=0;

x=-3π/4.

Флора · Answer 2

1. 2x+п/4=п/2+Пk

2x=п/4+Пk

x=п/8+Пk/2

2.

sin (x+П/2+п/4) = 0

cos (x+п/4) = 0

x=П/4+Пk

k∈Z

Cos (2x+pi/4) = 0sin (x+3pi/4) = 0