1. Решите уравнение 2x^2-x-10/x+2

2. 5x-9=2/x

3. (y-8) (y+4) / y-8=0

4. 2x^2-3x-9/x-3=2

1

(2x²-x-10) / (x+2) = 0

x+2≠0⇒x≠-2

2x²-x-10=0

D=1+80=81

x1 = (1-9) / 4=-2 U x2 = (1+9) / 4=2,5

2

5x-9=2/x

x≠0

5x²-9x-2=0

D=81+40=121

x1 = (9-11) / 10=-0,2

x2 = (9+11) / 10=2

3

(y-8) (y+4) / (y-8) = 0

y-8≠0⇒x≠8

y+4=0

y=-4

4

(2x²-3x-9) / (x-3) = 2

x-3≠0⇒x≠3

2x²-3x-9=2 (x-3)

2x²-3x-9-2x+6=0

2x²-5x-3=0

D=25+24=49

x1 = (5-7) / 4=-0,5

x2 = (5+7) / 4=3 не удов усл