Решите уравнение 2x^2-2x-12 = (x+2) ^2

2 х²-2 х-12 = (х+2) ²

2 х²-2 х-12=х²+4 х+4

2 х²-2 х-12-х²-4 х-4=0

х²-6 х-16=0

D=36+4*16*1=100

x₁=6+10/2=8

х₂=6-10/2=-2

2 х^2 - 2 х - 12 = (х + 2) ^2

2 (х^2 - х - 6) = (х + 2) ^2

2 (х^2 + 2 х - 3 х - 6) = (х + 2) ^2

2 (х • (х + 2) - 3 (х + 2)) = (х + 2) ^2

2 (х - 3) • (х + 2) = (х + 2) ^2

2 (х - 3) • (х + 2) - (х + 2) ^2 = 0

(х + 2) • (2 (х - 3) - (х + 2)) = 0

(х + 2) • (2 х - 6 - х - 2) = 0

(х + 2) • (х - 8) = 0

х + 2 = 0

х - 8 = 0

х = - 2

х = 8