lg (x+√3) + lg (x-√3) = 0

log₂ (x-2) + log₂ (x-3) = 1

lg (x²-9) - lg (x-3) = 0

log₆ (x-1) - log₆ (2x-11) = log₆2

log₀·₇log₄ (x-5) = 0

log²₀₋₅x-log₀₋₅x-2=0

Question

Алгебра

Мена

25 ноября, 02:39

lg (x+√3) + lg (x-√3) = 0

log₂ (x-2) + log₂ (x-3) = 1

lg (x²-9) - lg (x-3) = 0

log₆ (x-1) - log₆ (2x-11) = log₆2

log₀·₇log₄ (x-5) = 0

log²₀₋₅x-log₀₋₅x-2=0

+4

Ответы (1)

Знаете ответ на вопрос?

Прокоп · Answer 1

1) lg (x^2-3) = lg1

x^2-3=1

x=2

2) (x-2) (x-3) = 2

x^2-5x+4=0

x1=4

x2=1 x-3<0 не подходит

3) х+3=1

х=-2 не подходит по области определения, решений нет

4) (x-1) / (2x-11) = 2

x-1=4x-22

3x=21

x=7

5) log (x-5) = 0,7^0=1

x-5=4^1=4

x=9

6) log=t t^2-t-2=0

t1=2 t2=-1

x1=0,5^2=1/4

x2=0.5^ (-1) = 2

lg (x+√3) + lg (x-√3) = 0log₂ (x-2) + log₂ (x-3) = 1lg (x²-9) - lg (x-3) = 0log₆ (x-1) - log₆ (2x-11) = log₆2log₀·₇log₄ (x-5) = 0log²₀₋₅x-log₀₋₅x-2=0

lg (x+√3) + lg (x-√3) = 0

log₂ (x-2) + log₂ (x-3) = 1

lg (x²-9) - lg (x-3) = 0

log₆ (x-1) - log₆ (2x-11) = log₆2

log₀·₇log₄ (x-5) = 0

log²₀₋₅x-log₀₋₅x-2=0