Решите уравнение:

х (х^2-2) = х^3+8

(х+7) (х-7) - (х-3) ^2=53

7 х^2 = (2 х+1) ^2+3 х^2-5

(х+3) (х-2) - (х-3) (х+2) - 5=6 х-7

х^3+2 х^2-9 х-18=0

1)

х (х^2-2) = х^3+8

x^3 - 2x = x^3 + 8

x^3 - x^3 - 2x - 8 = 0

-2x - 8 = 0 | : 1

2x + 8 = 0

2x = - 8

x = - 8/2 = - 4

Ответ : - 4

2)

(х+7) (х-7) - (х-3) ^2=53

x^2 - 49 - x^2 + 6x - 9 - 53 = 0

6x - 111 = 0

6x = 111

x = 111/6

7 х^2 = (2 х+1) ^2+3 х^2-5

(2 х+1) ^2+3 х^2-5 = 7 х^2

4x^2 + 4x + 1 + 3x^2 - 5 - 7x^2 = 0

4x - 4 = 0

4x = 4

x = 1

Ответ: 1

(х+3) (х-2) - (х-3) (х+2) - 5=6 х-7

x^2 - 2x + 3x - 6 - x^2 - 2x + 3x + 6 = 6x - 7

2x = 6x - 7

-4x = - 7

x = 7/4