Найти область определения и указать множество значений функции

f (x) = 0,5arccos (4-5x) - 2

Y = arccos (x)

D (y) = [ - 1; 1]

E (y) = [ 0; pi]

y = arccos (5x)

D (y) = [ - 1/5; 1/5]

E (y) = [ 0; pi]

y = arccos (- 5x)

D (y) = [ - 1/5; 1/5]

E (y) = [ 0; pi]

y = arccos (4 - 5x)

D (y) = [ 3/5; 1]

E (y) = [ 0; pi]

y = 0,5*arccos (4 - 5x)

D (y) = [ 3/5; 1]

E (y) = [ 0; pi/2]

y = 0,5*arccos (4 - 5x) - 2

D (y) = [ 3/5; 1]

E (y) = [ - 2; pi/2 - 2]