Помогите решить уравнение:

4 + (2-x) (x^2+5x) - (2-x) (2+x) (1+x) = 12x

(2 - x) (x^2 + 5x) - (2 - x) (2 + x) (1 + x) = 12x - 4

(2 - x) ((x^2 + 5x) - (2+x) (1+x) = 4 (3x - 1)

(2 - x) (x^2 + 5x - 2 - 2x - x - x^2) = 4 (3x - 1)

(2 - x) (2x - 2) = 4 (3x - 1)

2 (x - 1) (2 - x) = 4 (3x - 1)

(x - 1) (2 - x) = 2 (3x - 1)

2x - x^2 - 2 + x = 6x - 2

x^2 + 4x = 0

x (x + 4) = 0

x = 0; x = - 4

Ответ: x1 = 0; x2 = - 4