1-sinx=sinx 2cos2x=2. 5-5sinx=cos2x

1) 1 - sin x = Sin x

2Sin x = 1

Sin x = 1/2

x = (-1) ^n arcSin 1/2 + nπ, n∈Z

x = (-1) ^n π/6 + nπ, n∈Z

2) 2 Cos x = 2

Cos x = 1

x = 2πk, k∈Z

3) 5 - 5 Sin x = Cos2x

5 - 5Sin x = 1 - 2Sin² x

2 Sin² x - 5Sin x + 4 = 0

Sin x = t

2t² - 5t + 4 = 0

D = 1

t1 = 3/2

t2 = 1

a) Sin x = 3/2

нет решений

б) Sin x = 1

x = π/2 + 2πk, k∈Z