Найдите корень уравнения

arccos4x+arccos2x=пи/3

arcsin (2x) + arcsin (x) = π/3

cos (arcsin (2x) + arcsin (x)) = cos (π/3)

cos (arcsin (2x)) * cos (arcsin (x)) - sin (arcsin (2x)) * sin (arcsin (x)) = cos (π/3)

cos (arcsin (2x)) * cos (arcsin (x)) - 2x*x=1/2

корень (1-4 х^2) * корень (1-х^2) = 1/2+2x^2

2 корень (1-4 х^2) * корень (1-х^2) = 1+4x^2

4 * (1-4 х^2) * (1-х^2) = (1+4x^2) ^2

х^2=t

4 * (1-4t) * (1-t) = (1+4t) ^2

4 * (1-5t+4t^2) = 1+8t+16t^2

4-20t=1+8t

3=28t

t=3/28

x=корень (3/28)