Y-3x=2 x2-2y=3 система уравнений

{y-3x=2

{x²-2y=3

y=2+3x

x²-2 (2+3x) = 3

x²-4-6x=3

x²-6x-4=3

x²-6x-4-3=0

x²-6x-7=0

D=-6²-4*1 (-7) = 36 - (-28) = 64=8

x¹=6-8/2*1=-2/2=-1

x²=6+8/2*1=14/2=7

y-3 (-1) = 2 - 1²-2y=3

y - (-3) = 2 1-2y=3

y+3=2 2y=1-3

y=2-3 2y=-2

y=-1 y=-2:2

y=-1

y-3*7=2 7²-2y=3

y-21=2 49-2y=3

y=2+21 2y=49-3

y=23 2y=46

y=46:2

y=23

Ответ: (-1; -1) (7; 23)