В) 30-x=3 (20-x)

д) 12-y=5 (4-2y) + 10

е) 2-2 (x-8) = 4x-4

В) 30-x = 3 (20-x)

30-x=60-3x

-x+3x=60-30

2x=30

x=15

30-15=3 (20-15)

15 = 15

Ответ: 15

д) 12-y = 5 (4-2y) + 10

12-y=20-10y+10

12-y=30-10y

-y+10y=30-12

9y=18

y=2

12-2=5 (4-2*2) + 10

10 = 5*0 + 10

10=10

Ответ: 2

е) 2-2 (х-8) = 4 х - 4

2-2 х+16=4 х - 4

-2 х+18 = 4 х - 4

-2 х-4 х=-4-18

-6 х = - 22

х=22/6

х=11/3

2-2 (11/3 - 8) = 4 (11/3) - 4

2 - 2 * (-13/3) = 44/3 - 4

2 + (26/3) = 44/3 - 12/3

32/3 = 32/3

Ответ: 11/3