1) 2root (5-2X) - 2root (X+17) = 0

2) X^2-2 - (X^2+8) / (X^2+2) = 0

3) 2 / (X^2-X-12) + 6 / (X^2+4X+3) = 1 / (X+3)

1) ОДЗ 5-2x≥0⇒x≤2,5 U x+17≥0⇒x≥-17

x∈[-17; 2,5]

2√ (5-2x) = 2√ (x+17)

5-2x=x+17

x+2x=5-17

3x=-12

x=-4

2) x²-2 = (x²+8) / (x²+2)

x^4-4-x²-8=0

x^4-x^2-12=0

x²=a

a²-a-12=0

a1+a2=1 U a1*a2=-12

a1=-3⇒x²=-3 нет решения

a2=4⇒x²=4⇒x=+-2

3) 2 / (x-4) (x+3) + 6 / (x+1) (x+3) = 1 / (x+3)

x≠4 x≠-3 x≠-1

2 (x+1) + 6 (x-4) = (x+1) (x-4)

x²-4x+x-4-2x-2-6x+24=0

x²-11x+18=0

x1+x2=11 U x1*x2=18

x1=2 x2=9