Решите систему

(4x+1) ^2=12y

(x+4) ^2=3y

16x²+8x+1=12y

x²+8x+16=3y

y = (x²+8x+16) / 3

16x²+8x+1=12 * (x²+8x+16) / 3

16x²+8x+1 = (12x²+96x+192) / 3

3 (16x²+8x+1) = 12x²+96x+192

48x²+24x+3=12x²+96x+192

48x²+24x+3-12x²-96x-192=0

36x²-72x-189=0

D=5184+27216=32400=180²

x₁ = (72+180) / 72=3,5

x₂ = (72-180) / 72=-1,5

y₁ = (3,5²+8*3,5+16) / 3 = (12,25+28+16) / 3=56,25/3=18,75

y₂ = (1,5²+8*1,5+16) / 3 = (2,25+12+16) / 3=30,25/3=10,1